47x^2+88x+39=0

Solution for 47x^2+88x+39=0 equation:

47x^2+88x+39=0

a = 47; b = 88; c = +39;
Δ = b2-4ac
Δ = 882-4·47·39
Δ = 412
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{412}=\sqrt{4*103}=\sqrt{4}*\sqrt{103}=2\sqrt{103}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(88)-2\sqrt{103}}{2*47}=\frac{-88-2\sqrt{103}}{94}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(88)+2\sqrt{103}}{2*47}=\frac{-88+2\sqrt{103}}{94}
$